a^2+17a+70=0

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Solution for a^2+17a+70=0 equation: 



a^2+17a+70=0

a = 1; b = 17; c = +70;
Δ = b2-4ac
Δ = 172-4·1·70
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-3}{2*1}=\frac{-20}{2}
=-10
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+3}{2*1}=\frac{-14}{2}
=-7
$

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